A treatment plant operator adding 200 lbs/day of alum at 48% purity to 2.5 MGD has an alum dose of?

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Multiple Choice

A treatment plant operator adding 200 lbs/day of alum at 48% purity to 2.5 MGD has an alum dose of?

Explanation:
The key idea is to convert the daily amount of alum actually entering the plant into a concentration (mg/L) based on the daily water volume. First apply the purity: 200 lb/day × 0.48 = 96 lb/day of active alum. Then use the standard conversion for dosing: mg/L = lbs/day ÷ (MGD × 8.34). So the dose is 96 ÷ (2.5 × 8.34) ≈ 96 ÷ 20.85 ≈ 4.6 mg/L, which rounds to about 5 mg/L. If you didn’t account for purity, you’d get roughly 9.6 mg/L (about 10 mg/L).

The key idea is to convert the daily amount of alum actually entering the plant into a concentration (mg/L) based on the daily water volume. First apply the purity: 200 lb/day × 0.48 = 96 lb/day of active alum. Then use the standard conversion for dosing: mg/L = lbs/day ÷ (MGD × 8.34). So the dose is 96 ÷ (2.5 × 8.34) ≈ 96 ÷ 20.85 ≈ 4.6 mg/L, which rounds to about 5 mg/L. If you didn’t account for purity, you’d get roughly 9.6 mg/L (about 10 mg/L).

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